$\left(d+6\right)^2=9$
$cot2\theta=-0,8$
$\sqrt{\sqrt[50000000000]{3.1416}}$
$x^2+x^2+4x+9$
$4\cdot2x^3$
$y'=2\left(1+x\right)\left(1+y^2\right)$
$\frac{\frac{x^2+6x+9}{x}}{x+3}$
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