$\lim_{x\to\infty}\left(\frac{32x^6-8}{4x^6-7x^5}\right)$

$\lim_{x\to\infty}\left(\frac{2x-1}{x\left(x-1\right)}\right)$

$x\left(x+3\right)^3$

$\lim_{x\to0}\left(\frac{sinx^5}{x}\right)$

$5\cdot8\cdot6$

$-15\left(-4\right)+2\left|-3\left(2\right)+\left(6\right)\left(8\right)\right|$

$3 x + 6 > 2 x + 12$