$\frac{u^2+8}{u^2-5u+6}$
$8x^2-121>7x^2-120$
$\frac{\left(2a^{\frac{7}{8}}\right)\left(18c^9\right)\left(-b^{\frac{2}{9}}\right)}{\left(a^{\frac{8}{1}}\right)\left(-6c^3\right)}$
$x^2+6x\le0$
$\left(-3567\right)\left(450\right)$
$\sqrt{\frac{\sqrt{x^4}}{9}}$
$\lim_{x\to2}\left(\frac{\sqrt{\left(x^2-5x+6\right)^3}}{x-2}\right)$
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