$\int\frac{5}{\sqrt{x^2-4x+9}}xdx$
$1.6667^3$
$\left(x^2+6x+5\right)\left(x-1\right)$
$\left(x-\frac{8}{3}\right)\left(x-\frac{9}{4}\right)$
$8-4\cdot5+3$
$y'=x^2\cdot e^x$
$\frac{4x^3-3x^2+x+1}{x+1}$
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