$\lim_{x\to\infty}\left(\frac{5\cdot x^2+1}{e^x}\right)$
$\left(2p\:-3y\right)^2$
$50ab-40ab$
$4b-7\:-15b\:+\:3$
$-25\cdot8$
$\frac{\sqrt{n}\left(2x+1\right)^{3n}}{n^2}$
$\frac{\cot\left(x\right)-\csc\left(x\right)}{1-\sec\left(x\right)}=\cot\left(x\right)$
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