$9^0-4$
$\frac{1}{4}\cdot\frac{1}{\frac{1}{4}}=1$
$.001+.1$
$\frac{xdx}{x^2+1}=\frac{\cos\left(y\right)}{\sin\left(y\right)}dy$
$\left(2x+7\right)+\left(2x+7\right)+\left(2x\right)+\left(2x\right)$
$-5x^2+7x-6$
$\left(.06+7.4\right)^2-14$
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