$\int\left(\frac{1}{\left(1-6t\right)^8}\right)dt$
$-\frac{15}{5}$
$-3x\le24$
$\int-u^3e^{-\cos\left(n\right)}du$
$\left(\sec\left(x\right)+1\right)\left(\sec\left(x\right)+1\right)=\tan\left(x\right)^2$
$-24x-12$
$4p^2.\:6p\:.\:4p^2$
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