$\int_0^0dx$
$\int\frac{1}{\left(x-3\right)^2\left(x+1\right)}dx$
$\frac{1}{3x+x^2}$
$\left(7ew\:-\:3x\right)\left(-7ew\:-\:3x\right)\:$
$\frac{dy}{dx}=-13xy^2$
$\frac{d^2}{dx^2}\left(8\sqrt{x}\right)$
$0.4+0.2+0.6+1.2$
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