$x^2-8x-64=0$
$8\sin^2-4=0$
$x2<-32x-256$
$\int sin^3\left(x\right)\cdot cos\left(y\right)dx$
$3x-4xy+7x^2y+5xy^2$
$9m^2+12m+4m$
$\frac{4x}{9}-\frac{1}{3}=\frac{2x+1}{5}$
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