$\frac{\sin x\:-\:\sin\:3\:x\:}{\sin^2x-\cos^2x}=\:2\sin x$
$60\cdot\frac{3}{4}$
$x^2-8x-273$
$\sqrt[5]{x^5}+\sqrt[6]{x^6}+\sqrt[7]{x^7}$
$\frac{u^2-1}{u}dy=2ydu$
$\int\frac{1}{\left(x+5\right)x}dx$
$\int6z\sqrt{4+z^2}dx$
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