$\int_1^{\infty}\left(2x^{-\frac{4}{3}}\right)dx$
$\frac{b}{7}^4$
$1-sinx=cos2x$
$25\:-\:x\:4\:=\:25\:-\:4x$
$25+10s+s^2$
$\lim_{x\to2}\left(\frac{4x^2-8x}{2x^2-4x}\right)$
$e^{-x^8}\left(-8x^8+1\right)=0$
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