$126m^6-343n^3$
$\int_1^{\infty}\left(\frac{10}{x}\right)dx$
$\int\left(10x^3\left(5x^4-1\right)^7\right)dx$
$\frac{1}{\left(sen\theta\:\cdot\:\:cos\theta\:\right)}-cot\theta\:$
$\int\:x^6dx$
$q^2+q-12$
$\frac{3x^2+18x+48}{x-2}$
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