$\:x\:\frac{dy}{dx}\:+6y=3xy^{\frac{4}{3}}$
$\left(2+x\right)\left(m^2-6m+8\right)$
$-10x-6=-10x$
$\left(\frac{ax}{5}\sqrt{108a^4}b^2x\right)$
$16x^2-32x-16=0$
$a^4+4^2+16$
$-81\:r\:\:-13r\:-45$
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