$\left(3b-4\right)-\left(4b+6\right)$
$\frac{5x-3}{x^3+2x^2-3}$
$-\frac{1}{9}yx-\frac{1}{9}y^2$
$\left(3x+1\right)\left(3x+8\right)$
$10x<0$
$-x^2+6x+1$
$-3x^4+5x^2+2x-6+2x^4+x^3+8x+1$
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