$3+6+4+4y$

$\left(4g^4-6g^3+3g^2-g+12\right)+\left(4g-4\right)$

$\cos\:\theta\:\left(\sec\:\theta\:-\cos\:\theta\:\right)$

$2+3x<x-4$

$5x^2-22x=2$

$\frac{3+2x\sqrt{5^{2}+12^{2}}}{\frac{16}{5}-\frac{2}{5}\times3}$

$\left(x^2y^3+x\right)dx\:+\:\left(x^3y^2\right)dy\:=\:0$