$-1.5\left(x-2\right)+1>-2\left(x-4\right)$
$4>3x+6$
$\int\left(x^2+6x\right)\cos\left(2x\right)dx$
$\int\left(3x^2\tan\left(4x^3\right)\right)dx$
$-4\left(7\right)+\left(-35\right)\left(11\right)$
$\frac{4}{5x+25}=\frac{5}{x+5}-\frac{3}{5}$
$\left(-8x^3+5x^2+7x+3\right)\left(5x^2+6x+1\right)$
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