$100+40\cdot25+8\cdot\left(-15\right)+2\cdot\left(-10\right)$

$\int\frac{4x+10}{\left(x-2\right)\left(x-1\right)^2}dx$

$\left(4ab^2-6\right)^2$

$y=\frac{3}{2}x+8$

$\int_x^1\left(k\left(1-y\right)\right)dy$

$10v^2-5v-v+1+8v-2v^2$

$\frac{dy}{dx}=\frac{-16\cdot x+5\cdot y}{3\cdot x+y}$