$5g\:-\:7g\:+\:4\:+\:2g$
$\lim_{x\to\infty}\left(\frac{\log\left(x\right)^2}{\sqrt[3]{x}}\right)$
$\left(-5^7\right)^6$
$\sin\left(2x\right)sin\left(x\right)-cos\left(2x\right)cos\left(x\right)=-cos\left(x\right)$
$6x^2-4x+6$
$6x+3<10x+17$
$64x^3+125$
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