$\cos\left(x\right)\sqrt{1+\tan^2}$
$\left(4\left(\frac{15}{2}\right)+3\right)+\left(6\left(\frac{15}{2}\right)-12\right)$
$3x+6>x-2$
$\frac{dx}{dy}=e^{3y}-x$
$\left(\frac{1}{5}b+\frac{2}{3}y\right)^2$
$f\left(x\right)=\frac{x^2-4}{x^2}$
$\sqrt{9x^2y^6}$
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