$\frac{tan^2\left(x\right)}{\:sec\left(x\right)}=\frac{1-cos\left(x\right)}{cos\left(x\right)}$
$x+xy+2xy$
$\left(2ab^{4}\right)^{6}$
$12-\left(-8\right)-\left(-5\right)$
$-742-914$
$2x-5-3x+10$
$\lim_{x\to0}\frac{6x^3-4x}{2x^4+x}$
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