$y'\:+\:y\:tan\:x\:=\:sec\:x\:+\:3\:cos\:x$
$\int\frac{1}{x\left(x^4+4\right)}dx$
$x^2+8x+9=0$
$\frac{x}{1+\frac{1}{1+\frac{1}{x}}}$
$\lim_{x\to1}\left(\frac{ln\left(2-x\right)}{x-1}\right)$
$-3x^2-x+10$
$\left(a+c\right)^7$
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