$\frac{8x^4+6x^3-1}{2x^2}$
$2x^2+3x+7=0$
$h\left(\frac{1}{4}\right)=\frac{1}{\frac{4}{2}}-1$
$\lim_{x\to\infty}\:5x-10$
$\frac{\sin^2\left(x\right)\left(\sec\left(x\right)+\csc\left(x\right)\right)}{\left(\cos\left(x\right)\tan\left(x\right)\right)}$
$\int8\cdot\cos\left(-8x\right)dx$
$4\cdot\left(1\right)-\left(1\right)-\left(1\right)-\left(1\right)$
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