$\left(-7.980\right)\:-\:\left(+3.590\right)$
$2\sin\left(x\right)\cdot\cos\left(x\right)=\sin\left(x\right)$
$\lim_{x\to\infty}\left(\frac{-6x-17}{5x^2+2x-2}\right)$
$\int\frac{\left(2x-5\right)}{\left(3x^2-2\right)}dx$
$x^5-32\:=\:0$
$\lim_{x\to-\infty}\left(\frac{1}{x-4}\right)$
$\int_7^{\infty}\left(\frac{1}{x^2-16}\right)dx$
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