$in\:\left(t^3+3t\right)$
$\left(x^3-x^2+x\right)\left(x^2-1\right)$
$\frac { d y } { d x } = 2 y + x ^ { 2 } + 5$
$t^4+4t^2+4$
$13-\left(12+5\right)+\left\{-4-15+16\right\}$
$\lim_{x\to1}\left(\frac{\ln\left(x\right)^3}{x^2-1}\right)$
$\frac{1}{\left(\frac{2}{\infty}\right)}$
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