$tan^3\left(x\right)=tan\left(x\right)$
$2y^3-2x^3+2y+4x-7x+4x-4y$
$3x+4\cdot3x-4$
$\left(7-\left(a-b\right)\right)\left(7+\left(a-b\right)\right)$
$-3cd+5cd-5cd$
$4y-20y+25$
$x=secy$
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