$=\frac{3x+2}{x}$

$\left(\frac{1}{17}\right)^{-4}$

$\int\frac{\frac{\cos\left(x\right)}{\sin\left(x\right)}.\frac{1}{\cos\left(x\right)}}{\sin^k\left(x+1\right)}dt$

$\left(x^2-2xy\right)^2$

$\frac{d^2}{dx^2}\:6\:cos\left(3x+3\right)$

$a^5+2a^4+11a^3+\:10a^2+25a$

$9\cdot2+9$