$\lim_{x\to\infty}\left(\ln\left(\frac{x-3}{x+3}\right)\right)$

$-\frac{360}{-9}$

$25=25+5x$

$\lim_{x\to3}\left(\frac{1}{3-x}-\frac{4x}{9-x^2}\right)$

$36y^2-96y+64$

$m^5-5m^4+6m^3-30m^2+9m-45$

$\left(\cos\left(x\right)\right)\left(\tan\left(x\right)+\sin\left(x\right)\cot\left(x\right)\right)$