$\left(2a^2-5b^4\right)^3$
$\sqrt{16\cdot81}$
$\left(tan\:+cot\right)^2=sec^2.csc^2$
$2-4n$
$\int\left(x^2+2x\right)e^{3x+5}dx$
$3x^2+x-10=0$
$\frac{4\cot\left(u\right)-\tan\left(u\right)}{\cot\left(u\right)+\tan\left(u\right)}+1$
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