$\int\frac{x^2-3x-4}{\left(x+2\right)\left(x-1\right)\left(x+3\right)}dx$
$\left(3\right)^3-2^3$
$\frac{8p^2q+p^2q^2-4pq^2}{2pq}$
$5\left(5\right)\left(5\right)\left(-5\right)$
$-8-3\left|4+6\left(5^2-5\right)\right|$
$-5+tan\left(x\right)=\frac{-15+\sqrt{3}}{3}$
$\frac{x-1}{x^4-x^3-2x^2}$
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