$\frac{\left(3\left(-\frac{1}{3}\right)^3-14\left(\frac{1}{3}\right)^2-2\left(\frac{1}{3}\right)+c\right)}{1}$

$\frac{1}{2}x+4$

$16x^4-y^2$

$1000+b^3$

$x^2-4xy+2y\:=\:4$

$\log_{10}\left(x\right)=\frac{\log_{10}\left(4\right)}{\log_{10}\left(2\right)}$

$\lim_{x\to-\infty}\left(\frac{\left(5x-6\right)}{sqrt\left(3x^2+4\right)}\right)$