$5\left(x-2\right)y^3dy-3dx=0$
$\left(x-1\right)^2=x^2-2x+1$
$\frac{x^2-28}{x-2}$
$\left(-3\right)\left(-4\right)\cdot12$
$x\:^3-2x$
$-3\cdot5\:\frac{1}{3}-12$
$\frac{2x^6-2}{x+1}$
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