$\int x^2\left(x^4-1\right)^3dx$
$\left(2m^5-3\right)^2$
$1-\left(-27\right)$
$\frac{dy}{dx}=-\frac{2}{3}cos\:8x\:-\frac{4}{3}sen8x$
$2-8n+9n+10$
$\left(x^3-8\right)\left(x^3+12\right)$
$\int\left(x\cdot\sqrt[3]{w^3}\right)dx$
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