$cos2x-3cosx-3-cos^2x=sin^2x$
$12y^6+14y^3+4$
$5x^3-x$
$\frac{sec\:x\:-\:cos\:x}{sec\:x}$
$y=3-2y$
$\frac{2}{x}-3<-1$
$-\:19\:+\:\:-25\:+\:44\:-\:\left[\:+9\:+\:4\:-\:5\:+\:\left(-10\:-\:8\:\right)\right]$
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