$10^3\:x\:10^5\:x\:10^8$
$\:3x^2-2x+4$
$\int\frac{t^{2}}{\left(t^{2}+4\right)^{4}}dt$
$\left(5x^2-3x-4\right)$
$\left(x-8\right)\left(7x+4\right)$
$-4+1+11$
$\lim_{x\to\infty}\left(-x^2-x-3\right)$
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