$\sqrt[3]{\frac{4xy^3}{256x^4y^2}}$
$y'=x^2+y$
$\frac{5}{6}+\frac{1}{6}$
$6^{-2}\cdot6^1$
$120-45+36-54$
$\left(5i-0.5j\right)^2$
$-\frac{1}{5}m^6.\frac{2}{6}m$
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