$8 x ^ { 3 } + 4 x ^ { 2 } + 2 x - 4$
$2x+11=27$
$\lim_{x\to-\infty}\left(\frac{x+8}{x-4}\right)$
$\left(b^{-1}\right)^2$
$w=x^3+y^3$
$-11+3-9+2$
$\left(x-2\right)^n\cdot\left(-1\right)^{n+1}\cdot\frac{1}{n^2}$
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