$\left(1-\cos^2x\right)\cot\left(x\right)$

$\frac{4x-3}{12}+\frac{3x+4}{8}\ge1+\frac{5x}{6}$

$\frac{\left(sec^2\left(x\right)sin\left(x\right)\right)}{tan\left(x\right)}$

$12x^2\:+17x+6$

$\left(-3\right)^2\cdot\left(-3\right)^2$

$4-12-28$

$\lim_{x\to1}\left(\frac{x^2-10x\:-11}{ln\left(x\right)}\right)$