$\frac{5x^3-x^2+3}{x^2+4}$
$3\:2\:x\:5\:+7\:x\:4$
$x^2-41x+400$
$3x=9x$
$2^5+1$
$\left(-2x\right)\left(-3\right)\left(y-4\right)$
$6p+2p-18$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!