$\frac{2x^3+8x+32}{-12x-24}$

$y=u^2-u\:$

$\int7x\cos\left(2-x^2\right)dx$

$\frac{5+x}{4}\le2x+6$

$-12\cos\left(6x\right)\sin\left(6x\right)+16\sin\left(8x\right)\cos\left(8x\right)$

$\frac{6^5\cdot6}{6^5}$

$\lim_{x\to\infty}\left(\frac{\ln\left(x\right)}{x^2+1}\right)$