$4\cdot4\cdot4\cdot4\cdot20$
$\left(x^2+1\right)\left(\tan\left(y\right)\frac{dy}{dx}=x\right)$
$3x+9=4x+5$
$y'=\frac{x-y}{\:2x}$
$6x+5=47$
$6y^3+2y^3$
$\left(y^2+8\right)\left(y^2-8\right)$
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