$\lim_{x\to3}\left(4x\right)$
$\left(-\frac{2}{3}m^2n+3mn^2\right)$
$7x^4-5x^3+3x^2-4x-1$
$\lim_{x\to3}\left(\frac{2x-1}{\sqrt{3x+1}}\right)$
$y'=y^2+2y-15$
$\int\frac{2x^2+9x}{\left(x^2+3\right)\left(x^2-2x+3\right)}dx$
$y^2-4y=\cos3a$
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