$\lim_{x\to-2}\left(\frac{x+1}{x^2-4}\right)$
$\lim_{x\to\infty}\left(\frac{x^4}{e^{8x}}\right)$
$\left(9+4v\right)^2$
$-30=-3y$
$9-10a+1$
$\frac{dy}{dx}=x\cdot e^{3x}-2y$
$\lim_{x\to5}\left(x^2+x\right)$
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