$\left(\frac{4x}{3b}\right)^4$
$-0,23\:+0,7$
$\frac{3x^3-5x^2+17x-18}{x-2}$
$\left(3xy\right)\left(-6x+y\right)$
$4x^{2+24x+36}$
$\left(6x+7\right)+\left(4x+5\right)\left(4x+6\right)$
$9y^2-1y+1$
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