$\lim_{x\to\infty}\:\frac{\left(21x-7\right)}{\sqrt{9x^2+5x}}$
$-\frac{1}{u-2}-\frac{u}{1}$
$\left(2x+8\right)\left(2x-8\right)$
$\frac{1}{x^2-5x+6}\le\frac{1}{2}$
$729\sqrt[6]{x^5}$
$\frac{3a^5+5a^2-12a+10}{a^2+2}$
$3a^2+a^2b-a^2-6ab-2b^2$
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