$-3x^2+4x-2$
$2tg4x=1$
$\frac{3x^2+20x+24}{x+5}$
$\frac{d}{dx}3xy^3=7x+2$
$8\:x\:7\:-\:10$
$\left(5d+2e\right)^2$
$\cot\left(x\right)\cos\left(x\right)+\frac{-\cos\left(x\right)}{\sec\left(x\right)+\tan\left(x\right)}$
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