$x+\frac{2}{x}=4$
$x^3-729$
$4^7\cdot9$
$\frac{2x^2+3x+d}{\sqrt[3]{x}}$
$f\left(x\right)=\left(1-2x\right)^8$
$x\:2\:-\:9x\:+\:8$
$\frac{2x^3-3x^2-5x+1}{x-2}$
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