$5x^2+9x^2$
$-2^1$
$x+\frac{1}{x}-5=\frac{5}{3}$
$-3\left(-6x+9\right)+1$
$\left(-8x^2y^3\right)\left(-9ab^4x^5\right)$
$-6=\frac{n}{2}-10$
$\left(6x-3\left(-4\right)\right)$
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