$\frac{sin2x}{1-tan^2x}=cos^2xtan2x$
$\lim_{x\to\infty}\left(\frac{x^3-2x^2+3}{x^5-2x^3+6}\right)$
$\lim_{x\to0}\left(1+sin\left(2x\right)^{\frac{1}{x}}\right)$
$83\left(-1\right)^2$
$\left(6mn^4\right)\left(3m^3p\right)$
$17\:-\:3p=16\:-\:4p$
$4x^2+7x-11$
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