$\int\:\frac{x^3-x+4}{x^2}dx$
$\int\frac{9}{\left(1+9u\right)}du$
$x\cdot\left(4x^2+3x+2\right)$
$\left(2x^2y^2-\frac{1}{5}wz\right)^3$
$\frac{x}{6}=-3$
$\frac{x^4}{x^2+1}$
$\frac{2a^4-a^3-21a^2+7a+4}{2a^2+5a-4}$
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