$-4x^2-20x-9$
$\left(9-z^2\right)\left(9-3z^2\right)$
$\left(-1\right)^4\cdot\left(-1\right)^3$
$3-\frac{6-4x}{2}<8$
$\left(4\right)\:+\:\left(2\right)\:+\:\left(-\:7\right)\:+\:\left(3\right)\:+\:\left(-\:2\right)\:$
$-1\:+\:5\:+\:1\:-\:4\:-\:1\:-\:2\:$
$\sqrt[12]{x^3}y^7$
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