$\frac{\sin^2\left(x\right)-\cos^2\left(x\right)}{\sin^2\left(x\right)}=1-\cot^2\left(x\right)$

$16+4\left(8-3\left(10+2\right)-5\left(4+9\right)\right)$

$f\left(x\right)=\left(2+x\right)^2$

$\int\left(4-2t^2\right)^7\cdot tdt$

$16cosx-3=\sqrt{128}-3$

$x^3-4x^2-x+4$

$\left(x^2-x^{\frac{1}{2}}\right)\left(x^2-x^{\frac{1}{2}}\right)$